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15n^2+26n-21=0
a = 15; b = 26; c = -21;
Δ = b2-4ac
Δ = 262-4·15·(-21)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-44}{2*15}=\frac{-70}{30} =-2+1/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+44}{2*15}=\frac{18}{30} =3/5 $
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